Heat rejected by the steam engine per minute will be equal to latent heat per minute plus heat rejected by the water to cool down.
ΔtΔH=ΔtΔmL+ΔtΔmsΔT⇒ΔtΔH=50×540+50×1×80=31000calmin−1=31×103calmin−1
JEE Main 2022 — Physics Thermodynamics
A steam engine intakes 50g of steam at 100∘C per minute and cools it down to 20∘C. If latent heat of vaporization of steam is 540calg−1, then the heat rejected by the steam engine per minute is _____ ×103cal
(Given : specific heat capacity of water : 1calg−1C∘−1)
Held on 25 Jun 2022 · Verified 6 Jul 2026.
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