Total surface area of a cube is 6a2=24m2⇒a2=4 ⇒a=2m
Volume of a cube V=a3=8m3
Change in volume is given by,
ΔV=V0γΔT, where γ=3α
ΔV=[8]×[1.5×10−4]×[10]m3⇒ΔV=1.2×105cm3
JEE Main 2022 — Physics Thermodynamics
A solid metallic cube having total surface area 24m2 is uniformly heated. If its temperature is increased by 10∘C, calculate the increase in volume of the cube. (Given α=5.0×10−4C∘−1).
Held on 25 Jun 2022 · Verified 6 Jul 2026.
2.4×106cm3
1.2×105cm3
6×104cm3
4.8×105cm3
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