Loss of kinetic energy of the lead bullet=Heat generated to raise its temperature from 127∘C to 327∘C.
40 loss of the kinetic energy of the lead bullet=Heat gained by the lead bullet to raise its temperature.
0.4(21mv2)=m×[SPb×ΔT+m×LPb]
0.4×21mv2=mSPb(T2−t1)+mLPb
0.2mv2=m×[125×(327−127)+2.5×104]
v2=5×[125×200+2.5×104]
v2=5×[25000+25000]
v=500ms−1