Given here, P1=2×107Nm−2=2×107Pa
Using Boyle's law,
P1V1=P2V2
Since V2=2V1.
Hence, P2=2P1 (isothermal expansion)
P2=1×107Pa
Now, during adiabatic expansion,
P2(V2)γ=P3(2V2)γ
P3=21.51×107=3.536×106Pa
JEE Main 2022 — Physics Thermodynamics
A certain amount of gas of volume V at 27∘C temperature and pressure 2×107Nm−2 expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use γ=1.5)
Held on 25 Jul 2022 · Verified 6 Jul 2026.
3.536×105Pa
3.536×106Pa
1.25×106Pa
1.25×105Pa
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