We know that work done is W=∫PdV...(1)
⇒P=VnRT...(2)
⇒W=∫VnRTdv...(3)
and V=KT2/3...(4)
⇒W=∫KT2/3nRT⋅dv...(5)
⇒ from (4):dv=32KT−1/3dT
⇒W=∫T1T2KT2/3nRT32KT1/31dT
⇒W=32nR×(T2−T1)...(6)
⇒T2−T1=90K...(7)
⇒W=32nR×90
⇒W=60nR
Assuming 1 mole of gas
n=1
So W=60R