S=α2βℓn(Jβ2μkR+3)
S=TQ=Joulek−1
[α2β]=Joulek−1
PV=nRT[Jβ2μkR]=1
R=k Joule
⇒R=k Joule ,k=R Joule
⇒β=(k Joule )
α2β=(k Joule )
⇒α= dimensionless
JEE Main 2021 — Physics Thermodynamics
The entropy of any system is given by,
S=α2βln[Jβ2μkR+3]
where α and β are the constants. μ,J,k and R are number of moles, mechanical equivalent of heat, Boltzmann's constant and gas constant, respectively.
[Take S=TdQ]
Choose the incorrect option from the following:
Held on 20 Jul 2021 · Verified 6 Jul 2026.
α and J have the same dimensions.
S,β,k and μR have the same dimensions.
S and α have different dimensions.
α and k have the same dimensions.
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