ΔQ=ΔU+ΔW
Here ΔW=0
ΔQ=ΔU=nCVΔT
ΔQ=4×25R(50)=500R
Hence option (4).
JEE Main 2021 — Physics Thermodynamics
The amount of heat needed to raise the temperature of 4moles of a rigid diatomic gas from 0∘C to 50∘C when no work is done is(R is the universal gas constant)
Held on 20 Jul 2021 · Verified 6 Jul 2026.
250R
750R
175R
500R
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