Work done in adiabatic process =γ−1−nR(Tf−Ti)
∴WAD=γ−1−nR(T2−T1)
and WBC=γ−1−nR(T2−T1)
∴WAD=WBC
JEE Main 2021 — Physics Thermodynamics
In the reported figure, there is a cyclic process ABCDA on a sample of 1 mol of a diatomic gas. The temperature of the gas during the process A→B and C→D are T1 and T2(T1>T2) respectively.

Choose the correct option out of the following for work done if processes BC and DA are adiabatic.
Held on 27 Jul 2021 · Verified 6 Jul 2026.
WAB=WDC
WAD=WBC
WBC+WDA>0
WAB<WCD
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