CP−CV=R for ideal gas and gas behaves as ideal gas at high temperature, so TP>TQ.
For a gas C_ P-C_ V=R in a state P and C_ P-C_ V=1.10R in a state Q,T_ P and T_ Q are the temperatures in two different states P and Q, respectively.…
JEE Main 2021 — Physics Thermodynamics
For a gas CP−CV=R in a state P and CP−CV=1.10R in a state Q,TP and TQ are the temperatures in two different states P and Q, respectively. Then
Held on 25 Jul 2021 · Verified 6 Jul 2026.
Options
- A
TP=TQ
- B
TP<TQ
- C
TP=0.9TQ
- D
TP>TQ
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Thermodynamics in other years
More JEE Main Thermodynamics questions
The temperature of a metal strip having coefficient of linear expansion $\alpha$ is increased from $T_1$ to $T_2$ resulting in increase of its length by $\Delta L_1$. The temperature is further increased from $T_2$ to $T_3$ such that the increase in its length is $\Delta L_2$. Given $T_3+T_1=2T_2$ and $T_2-T_1=\Delta T$, the value of $\Delta L_2$ is ______.
The mean free path of a molecule of diameter $5 \times 10^{-10} \mathrm{~m}$ at the temperature $41^{\circ} \mathrm{C}$ and pressure $1.38 \times 10^{5} \mathrm{~Pa}$, is given as $\_\_\_\_$ m. (Given $k_{B}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$).
Two closed vessels of same volume are joined through a narrow tube and both vessels are filled with air of pressure $90$ kPa and temperature $400$ K. Keeping the temperature of one vessel constant at $400$ K the second vessel temperature is raised to $500$ K. The final pressure in the vessels is _______ kPa.
Heat is supplied to a diatomic gas at constant pressure. Then the ratio of $\Delta Q : \Delta U : \Delta W$ is _______.
An ideal gas undergoes a process maintaining relation between pressure $(P)$ and volume $(V)$ as $P = P_o\left(1 + \left(\dfrac{V_o}{V}\right)^2\right)^{-1}$, where $P_o$ and $V_o$ are constants. If two samples $A$ and $B$ (two moles each) with initial volumes $V_o$ and $3V_o$ respectively undergo above mentioned process and attain same pressure, then the difference at the temperatures of these samples, $T_B - T_A$ is _____. ($R = $ gas constant)
Other Physics topics for JEE Main
Keep practicing Thermodynamics
Work through every JEE Main Thermodynamics PYQ, year by year.