The mass of ice, m=ρAL=103×10−4×1=10−1kg,
Energy required to melt the ice, =mSΔT+mL,
⇒i2Rt=mSΔT+mL
⇒(1)2×103×t=[(103×1×10−4)×2000×10]+[(103×1×10−4)×330×103]⇒(1)2×103×t=3.53×104⇒t=35.3s
Due to cold weather, a 1m water pipe of cross-sectional area 1 cm^2 is filled with ice at -10°C. Resistive heating is used to melt the ice. Current…
JEE Main 2021 — Physics Thermodynamics
2021mcqmedium
Due to cold weather, a 1m water pipe of cross-sectional area 1cm2 is filled with ice at −10∘C. Resistive heating is used to melt the ice. Current of 0.5A is passed through 4kΩ resistance. Assuming that all the heat produced is used for melting, what is the minimum time required?
(Given latent heat of fusion for water/ice=3.33×105Jkg−1, specific heat of ice =2\times {10}^{3}J{\mathrm{kg}}^{-1}^{\circ}{C}^{-1} and density of ice =103kgm−3)
Official previous-year question
Held on 1 Sept 2021 · Verified 6 Jul 2026.
Options
- A
3.53s
- B
0.353s
- C
35.3s
- D
70.6s
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