A number of moles of, O2=32m1, the number of moles of, H2=2m2. Using the ideal gas equation, PV=[32m1+2m2]325×300,
400×103×500×10−6=[32m1+2m2]25×100⇒2×102=[m2m1×321+21]m2×25×100
⇒252=[m2m1×321+21]m2...(1)
⇒m1+m2=0.76
⇒m2[1+m2m1]=10076...(2)
(1) divided by (2) ; [m2m1+1][m2m1×321+21]=252×76100
Let assume,
⇒m2m1=x⇒32[x+1]x+16=768⇒76x+76×16=8×32x+8×32⇒76x+1216=256x+256
960=180x⇒x=1896=316