For gas A
PAV=nART
PA=V(1)RT
for gas B
PBV=nBRT
PB=V(2)RT
Now according to the Dalton's law of mixture,
P=PA+PB
=V3RT=4×10−33×8.314(400)=24.9×105Pa
JEE Main 2021 — Physics Thermodynamics
A cylindrical container of volume 4.0×10−3m3 contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400K. The pressure of the mixture of gases is :
[Take gas constant as 8.3Jmol−1K−1]
Held on 26 Aug 2021 · Verified 6 Jul 2026.
24.9×103Pa
249×101Pa
24.9×105Pa
24.9Pa
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