P1=P1
v1=v1
T1=250
n1=n0
n2=0.75n0+2×0.25n0=1.25no
v2=2V1
T2=2000
P1V1=n1RT1
P2V2=n2RT2
P1V1=n0R×250
P2(2V1)=(.25n0R(2000))
equation (1)/(2)
2P2P1=1.25×2000250
P2P1=51
P1P2=5
JEE Main 2020 — Physics Thermodynamics
Initially a gas of diatomic molecules is contained in a cylinder of volume V1 at a pressure P1 and temperature 250K. Assuming that 25 of the molecules get dissociated causing a change in number of moles. The pressure of the resulting gas at temperature 2000K, when contained in a volume 2V1 is given by P2. The ratio P2/P1 is -
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