(0.1)(200)+(0.05)(400)=(0.15)T
T=0.1520+20=3800=266.67
=266.67
JEE Main 2020 — Physics Thermodynamics
A closed vessel contains 0.1 mole of a monoatomic ideal gas at 200 K. If 0.05 mole of the same gas at 400K is added to it, the final equilibrium temperature (in K) of the gas in the vessel will be close to ______
Held on 4 Sept 2020 · Verified 6 Jul 2026.
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