Change in length in both rods are same i.e. Δℓ1=Δℓ2 ℓα1Δθ1=ℓα2Δθ2 $\begin{array}{l}
\frac{\alpha_{1}}{\alpha_{2}}=\frac{\Delta \theta_{2}}{\Delta \theta_{1}} \quad\left[\because \frac{\alpha_{1}}{\alpha_{2}}=\frac{4}{3}\right] \
\frac{4}{3}=\frac{\theta-30}{180-30}
\end{array}\theta=230^{\circ} \mathrm{C}$