For ideal gas, PV=nRT
Therefore, VnRT=P0[1−21(VV0)2]
⇒T=RP0V[1−21(VV0)2]
Therefore, the change in temperature is:
ΔT=Tf−Ti
=RP0(2V0)(1−21(2V0V0)2)−RP0V(1−2V02V02)
=4R5P0V0
JEE Main 2019 — Physics Thermodynamics
One mole of an ideal gas passes through a process where pressure and volume obey the relation P=Po[1−21(VVo)2] . Here Po and Vo are constants. Calculate the change in the temperature of the gas if its volume changes from Vo to 2Vo .
Held on 10 Apr 2019 · Verified 6 Jul 2026.
41RP0V0
45RP0V0
21RP0V0
43RP0V0
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