V=2m3
P=3×106Pa
PV=nRT
E=2fnRT=2fPV=23×3×106×2
=9×106J
An ideal gas occupies a volume of 2m3 at a pressure of 3×106Pa. The energy of the gas is:
Held on 12 Jan 2019 · Verified 6 Jul 2026.
108J
9×106J
3×102J
6×104J
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