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A heat source at T=10^3K is connected to another heat reservoir at T=10^2K by a copper slab which is 1 m thick. Given that the thermal conductivity…

JEE Main 2019 — Physics Thermodynamics

2019mcqeasy

A heat source at T=103KT={10}^{3}KT=103K is connected to another heat reservoir at T=102KT={10}^{2}KT=102K by a copper slab which is 1m1 m1m thick. Given that the thermal conductivity of copper is 0.1WK−1m−10.1 W{K}^{-1} {m}^{-1}0.1WK−1m−1, the energy flux through it in the steady-state is:

Official previous-year question

Held on 10 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    65Wm−265 W{m}^{-2}65Wm−2

  2. B

    120Wm−2120 W{m}^{-2}120Wm−2

  3. C

    90Wm−290 W{m}^{-2}90Wm−2

  4. D

    200Wm−2200 W{m}^{-2}200Wm−2

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