For path ACB,
ΔQ=ΔU+ΔW
60=ΔU+30
⇒ΔU=30J
For path ADB
ΔQ=ΔU+ΔW
As initial and find points are the same, change in internal energy is same in both the cases
ΔQ=30+10
=40J
A gas can be taken from A to B via two different processes ACB and ADB. JEE Main 2019 Physics, Thermodynamics — question figure When path ACB is used…
JEE Main 2019 — Physics Thermodynamics
2019mcqmedium
A gas can be taken from A to B via two different processes ACB and ADB.
When path ACB is used 60J of heat flows into the system and 30J of work is done by the system. If the path ADB is used then work done by the system is 10J, the heat flows into the system in the path ADB is:
Official previous-year question
Held on 9 Jan 2019 · Verified 6 Jul 2026.
Options
- A
100J
- B
20J
- C
40J
- D
80J
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