Cp=27R (for diatomic gas)
ΔQ=nCpΔT (∴Isobaricprocess)
ΔW=nRΔT=10J
Given
∴ΔQ=n×27RΔT=27×10=35J nRΔT=10J
JEE Main 2019 — Physics Thermodynamics
A diatomic gas with rigid molecules does 10J of work when expanded at constant pressure. What would be the heat energy absorbed by the gas, in this process?
Held on 12 Apr 2019 · Verified 6 Jul 2026.
40J
35J
25J
30J
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