F=YAαΔt
⇒F=2×1011×40×10−4×1.2×10−5×10
⇒F=9.6×104≈1×105N.
JEE Main 2017 — Physics Thermodynamics
A steel rail of length 5m and area of cross section 40cm2 is prevented from expanding along its length while the temperature rises by 10∘C . If coefficient of linear expansion and Young's modulus of steel are 1.2×10−5K−1 and 2×1011Nm−2 respectively, the force developed in the rail is approximately:
Held on 9 Apr 2017 · Verified 6 Jul 2026.
2×107N
2×109N
3×10−5N
1×105N
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