mcb=100g,mc=100g,mw=170g,(ToC)(30oC)(30oC)
Net heat loss = Net heat gain
⇒100×0.1×(T−75)=100×0.1×(75−30)+170×1×(75−30)
⇒T−75=45+17×45
⇒T=885∘C.
JEE Main 2017 — Physics Thermodynamics
A copper ball of mass 100g is at a temperature T. It is dropped in a copper calorimeter of mass 100g, filled with 170g of water at room temperature. Subsequently, the temperature of the system is found to be 75∘C. T is given by:
(Given: room temperature =30∘C, specific heat of copper =0.1 \mathrm{cal}{g}^{-1} ^{\circ}{C}^{-1})
Held on 2 Apr 2017 · Verified 6 Jul 2026.
825∘C
800∘C
885∘C
1250∘C
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