Temperature T will be maximum where product of PV is max equation of line
P=−V0P0V+3P0
Multiplying both sides by V,
PV=−V0P0V2+3P0V
For maxima, dVd(PV)=0
⇒V0−2P0V+3P0=0⇒V=23V0
andP=23P0
⇒T=nRPV=4nR9P0V0
Alternate method :
Since initial and final temperature are equal.
Hence maximum temperature is at middle of line.
PV=nRTmax
⇒Tmax=nR(23P0)(23V0)=4nR9P0V0