PV=nRT+αV
dTP0dV=R+αdTdV
(P0−α)dTdV=R
∴dV=P0−αRdT
∴W=∫P0dV=∫T02T0P0−αP0RdT
=P0−αP0T0R
JEE Main 2014 — Physics Thermodynamics
The equation of state for a gas is given by PV=nRT+αV, where n is the number of moles and α is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are T0 and P0 respectively. The work done by the gas when its temperature doubles isobarically will be :
Held on 9 Apr 2014 · Verified 6 Jul 2026.
P0T0ln2
P0+αP0T0R
P0−αP0T0R
P0T0R
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