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A gas molecule of mass M at the surface of the earth has kinetic energy equivalent to 0°C. If it were to go up straight without colliding with any…

JEE Main 2014 — Physics Thermodynamics

2014mcqmedium

A gas molecule of mass MMM at the surface of the earth has kinetic energy equivalent to 0∘C0^{\circ}C0∘C. If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than the radius of the earth. (kB{k}_{B}kB​ is Boltzmann constant)

Official previous-year question

Held on 19 Apr 2014 · Verified 6 Jul 2026.

Options

  1. A

    273kB2Mg\frac{273{k}_{B}}{2Mg}2Mg273kB​​

  2. B

    819kB2Mg\frac{819{k}_{B}}{2Mg}2Mg819kB​​

  3. C

    000

  4. D

    546kB3Mg\frac{546{k}_{B}}{3Mg}3Mg546kB​​

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