Mgh=21Mvrms2
=21Mm3kT
⇒vrms2=M819k
Now apply v2=u2−2gh undefined
A gas molecule of mass M at the surface of the earth has kinetic energy equivalent to 0∘C. If it were to go up straight without colliding with any other molecules, how high it would rise? Assume that the height attained is much less than the radius of the earth. (kB is Boltzmann constant)
Held on 19 Apr 2014 · Verified 6 Jul 2026.
2Mg273kB
2Mg819kB
0
3Mg546kB
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