As 1 g of steam at 100∘C melts 8 g of ice at 0∘C. 10 g of steam will melt 8×10 g of ice at 0∘C Water in calorimeter =500+80+10 g=590 g
JEE Main 2013 — Physics Thermodynamics
500 g of water and 100 g of ice at 0∘C are in a calorimeter whose water equivalent is 40 g.10 g of steam at 100∘C is added to it. Then water in the calorimeter is : (Latent heat of ice =80cal/g, Latent heat of steam =540cal/g )
Held on 23 Apr 2013 · Verified 6 Jul 2026.
580 g
590 g
600 g
610 g
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