As the surrounding is identical, vessel is identical time taken to cool both water and liquid (from 30∘C to 25∘C ) is same 2 minutes, therefore (dtdQ)water =(dtdQ)liquid or, t(mWCW+W)ΔT=t(mℓCℓ+W)ΔT (W= water equivalent of the vessel ) or, mwCw=mℓCℓ ∴ Specific heat of liquid, Cℓ=mℓmWCW =10050×1=0.5kcal/kg
A mass of 50 ~g of water in a closed vessel, with surroundings at a constant temperature takes 2 minutes to cool from 30° C to 25° C. A mass of 100…
JEE Main 2013 — Physics Thermodynamics
A mass of 50 g of water in a closed vessel, with surroundings at a constant temperature takes 2 minutes to cool from 30∘C to 25∘C. A mass of 100 g of another liquid in an identical vessel with identical surroundings takes the same time to cool from 30∘C to 25∘C. The specific heat of the liquid is : (The water equivalent of the vessel is 30 g.)
Held on 25 Apr 2013 · Verified 6 Jul 2026.
Options
- A
2.0kcal/kg
- B
7kcal/kg
- C
3kcal/kg
- D
0.5kcal/kg
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