For given graph, equation of P - V line is P−2P0=V0−2V02P0−P0(V−V0) So, P=3P0−V0P0V as PV=nRT ⇒(3P0−V0P0V)V=nRT; For maximum temperature dVdT=0 ⇒dVdT=3P0−V02P0V=0⇒V=23V0 Also P=23P0 So, T=nRPV=nR1×23P0×23V0=4nR9P0V0
n moles of an ideal gas undergo a process A→B as shown in the figure. Maximum temperature of the gas during the process is 
Held on 12 May 2012 · Verified 6 Jul 2026.
nR9P0V0
2nR3P0V0
2nR9P0V0
4nR9P0V0
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