If temperature increases by ΔT, Increase in length L,ΔL=LαΔT ∴LΔL=αΔT Let tension developed in the ring is T. ∴ST=YLΔL=YαΔT ∴T=SYαΔT From FBD of one part of the wheel, F=2T Where, F is the force that one part of the wheel applies on the other part. ∴F=2SYαΔT 
A wooden wheel of radius R is made of two semicircular parts (see figure); The two parts are held together by a ring made of a metal strip of cross…
JEE Main 2012 — Physics Thermodynamics
A wooden wheel of radius R is made of two semicircular parts (see figure); The two parts are held together by a ring made of a metal strip of cross sectional area S and length L. L is slightly less than 2πR. To fit the ring on the wheel, it is heated so that its temperature rises by ΔT and it just steps over the wheel. As it cools down to surrounding temperature, it presses the semicircular parts together. If the coefficient of linear expansion of the metal is α, and its Youngs' modulus is Y, the force that one part of the wheel applies on the other part is : 
Held on 30 Apr 2012 · Verified 6 Jul 2026.
Options
- A
2πSYαΔT
- B
SYαΔT
- C
πSYαΔT
- D
2SYαΔT
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