Through P2I1=I0sin2(2π−θ)
I1=I0cos2θ
Through P3Inet =(I0cos2θ)sin2θ
Inct=4I0[sin(2θ)]2 for max Inet θ=45∘
So angle between P2 and P3=4π
Correct Ans. (1)
Two polarisers P1 and P2 are placed in such a way that the intensity of the transmitted light will be zero. A third polariser P3 is inserted in between P1 and P2, at the particular angle between P2 and P3. The transmitted intensity of the light passing the through all three polarisers is maximum. The angle between the polarisers P2 and P3 is :
Held on 4 Apr 2025 · Verified 6 Jul 2026.
4π
6π
8π
3π
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