
n1×2n1n2=n2sinrsinr=21 r=30∘tanr=(td/2)t=2tanrd=2d3=2(43)3=6 cm
Two light beams fall on a transparent material block at point 1 and 2 with angle θ1 and θ2′ respectively, as shown in figure. After refraction, the beams intersect at point 3 which is exactly on the interface at other end of the block. Given : the distance between 1 and 2, d=43 cm and θ1=θ2=cos−1(2n1n2), where refractive index of the block n2> refractive index of the outside medium n1, then the thickness of the block is ________ cm. 
Held on 29 Jan 2025 · Verified 6 Jul 2026.
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