Applying Snell's law, we get
μasini=μgsin(90∘−i)
tani=μaμg
When going from glass to air
tani′=μgμa=coti
Clearly, i′=(2π−i) & hence Statement I is true but Statement II is false.
Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is θB, then Brewster's angle for the light propagating from glass to air is 2π−θB.
Statement II : The Brewster's angle for the light propagating from glass to air is tan−1(μg), where μg is the refractive index of glass.
In the light of the above statements, choose the correct answer from the options given below :
Held on 24 Jan 2023 · Verified 6 Jul 2026.
Both Statements I and Statement II are true.
Statement I is true but Statement II is false.
Both Statement I and Statement II are false.
Statement I is false but Statement II is true.
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