From lens maker’s formula,
f1=(μ−1)(R11−R21)
f11=(μ1−1)(∞1−(−R)1)=Rμ1−1
f21=(μ2−1)((−R)1−∞1)=−R(μ2−1)
feq1=f11+f21=Rμ1−1−Rμ2−1
=Rμ1−μ2
feq=μ1−μ2R
One plano-convex and one plano-concave lens of the same radius of curvature R but of different materials are joined side by side as shown in the figure. If the refractive index of the material of 1 is μ1 and that of 2 isμ2, then the focal length of the combination is:

Held on 10 Apr 2019 · Verified 6 Jul 2026.
2−(μ1−μ2)R
2(μ1−μ2)R
μ1−μ22R
μ1−μ2R
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