In figure, the optical fiber is l=2 m long and has a diameter of d=20 μ m. If a ray of light is incident on one end of the fiber at angle θ _1=40° ,…
JEE Main 2019 — Physics Optics
2019mcqmedium
In figure, the optical fiber is l=2m long and has a diameter of d=20μm. If a ray of light is incident on one end of the fiber at angle θ1=40∘ , the number of reflections it makes before emerging from the other end is close to:
(refractive index of fiber is 1.31 , sin40∘=0.64 and sin−10.49=30∘ .)
Official previous-year question
Held on 8 Apr 2019 · Verified 6 Jul 2026.
Options
A
55000
B
57000
C
45000
D
66000
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Solution
Let n1 and n2 be the refractive indices of the air and optical fibre respectively. Applying Snell's law at Q, we get:
n1sinθ1=n2sinθ2
sin40∘=1.31×sinθ2
⇒sinθ2=1.310.64=0.4885≈0.5
⇒θ2=30∘
The distance covered along the length of the optical fibre after one reflection:
QN=RNcotθ2
=20×10−6×cot30∘=203×10−6m
The reflections take place throughout the length of the optical fibre.
Length of the wire=2m
Total number of reflections along its length=distancecoveredinonereflectionalongthelengthLengthofthewire
=2032×106=3100000=57735.02≈57000
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