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A thin convex lens L (refractive index =1.5 ) is placed on a plane mirror M. When a pin is placed at A, such that OA=18 cm, its real inverted image…

JEE Main 2019 — Physics Optics

2019mcqhard

A thin convex lens LLL (refractive index =1.5=1.5=1.5 ) is placed on a plane mirror MMM. When a pin is placed at AAA, such that OA=18cm,OA=18 cm,OA=18cm, its real inverted image is formed at AAA itself, as shown in figure. When liquid of refractive index μl{\mu }_{l}μl​ is put between the lens and the mirror, the pin has to be moved to A′,{A}^{'},A′, such that OA′=27cm,O{A}^{'}=27 cm,OA′=27cm, to get its inverted real image at A′A'A′ itself. The value of μl{\mu }_{l}μl​ will be

JEE Main 2019 Physics, Ray Optics — question figure

Official previous-year question

Held on 9 Apr 2019 · Verified 6 Jul 2026.

Options

  1. A

    43\frac{4}{3}34​

  2. B

    3\sqrt{3}3​

  3. C

    32\frac{3}{2}23​

  4. D

    2\sqrt{2}2​

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