In a stable population, for a gene with two alleles, 'A' (dominant) and 'a' (recessive), the frequency of ' A′=p the frequency of ' a ' =q, According Hardy-Weinberg equation: p2+2pq+q2=1 where p2= Frequency of A (homozygous dominant) individuals q2= Frequency of aa (homozygous recessive) individuals 2pq= Frequency of Aa (heterozygous) individuals. ∴2pq( frequency of heterozygote )=2×0.6×0.4=0.48
At a particular locus, frequency of A allele is 0.6 and that of a is 0.4 . What would be the frequency of heterozygotes in a random mating population…
NEET UG 2005 — Zoology Evolution
2005mcqmedium
At a particular locus, frequency of A allele is 0.6 and that of a is 0.4 . What would be the frequency of heterozygotes in a random mating population at equilibrium?
Official previous-year question
Held on 30 Apr 2005 · Verified 9 Jul 2026.
Options
- A
0.36
- B
0.16
- C
0.24
- D
0.48
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