K=WQ2=t2t1−11
Q2=t1−t2t2W.
Q1=Q2+W=t1−t2t2W+W
=t1−t2t1W.
Since, {t}_{1}&{t}_{2} are in {}^{o}C &W = 1 J,
Q1=t1−t2t1+273.
The temperature inside a refrigerator is t2oC and the room temperature is t1oC. The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
Held on 30 Apr 2016 · Verified 9 Jul 2026.
t1−t2t1
t1−t2t1+273
t1−t2t2+273
t1+273t1+t2
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