Rate =−21dtd[ N2O5]=41dtd[NO2]=dtd[O2]⇒21k[ N2O5]=41k′[N2O5]=k′′[N2O5] ⇒2k∴=4k′=k′′k′=2k;k′′=2k
NEET UG 2011 — Chemistry Physical Chemistry
The rate of reaction 2 N2O5⟶4NO2+O2 can be written in three ways dt−d[ N2O5]dtd[NO2]dtd[O2]=k[ N2O5]=k′[N2O5]=k′′[N2O5] The relationship between k and k′ and between k and k′′ are
Held on 30 Apr 2011 · Verified 9 Jul 2026.
k′=2k;k′=k
k′=2k;k′′=k/2
k′=2k;k′′=2k
k′=k;k′′=k
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