∵π=CRT=M×V( in mL )w×1000×RT[∵C=V( in mL )n×1000 and n=Mw]=2.57×10−3×2001.26×1000×0.083×300=61038 g mol−1
NEET UG 2011 — Chemistry Physical Chemistry
200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.57×10−3 bar. The molar mass of protein will be
Held on 30 Apr 2011 · Verified 9 Jul 2026.
51022 g mol−1
122044 g mol−1
31011 g mol−1
61038 g mol−1
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