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Consider the following processes Δ H( ~kJ / mol) … For B+D → E+2 C, Δ H will be

NEET UG 2011 — Chemistry Physical Chemistry

2011mcqmedium

Consider the following processes ΔH( kJ/mol)\Delta H(\mathrm{~kJ} / \mathrm{mol})ΔH( kJ/mol) 1/2A→B+1503B→2C+D−125E+A→2D+350\begin{array}{ll}1 / 2 A \rightarrow B & +150 \\ 3 B \rightarrow 2 C+D & -125 \\ E+A \rightarrow 2 D & +350\end{array}1/2A→B3B→2C+DE+A→2D​+150−125+350​ For B+D→E+2C,ΔHB+D \rightarrow E+2 C, \Delta HB+D→E+2C,ΔH will be

Official previous-year question

Held on 30 Apr 2011 · Verified 9 Jul 2026.

Options

  1. A

    525 kJ/mol525 \mathrm{~kJ} / \mathrm{mol}525 kJ/mol

  2. B

    −175 kJ/mol-175 \mathrm{~kJ} / \mathrm{mol}−175 kJ/mol

  3. C

    −325 kJ/mol-325 \mathrm{~kJ} / \mathrm{mol}−325 kJ/mol

  4. D

    325 kJ/mol325 \mathrm{~kJ} / \mathrm{mol}325 kJ/mol

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