
For polybasic acid, order of ionization constant is Ka1>Ka2>Ka3 because as negative charge increases, tendency to loose H+ions decreases. Overall K=Ka1×Ka2×Ka3 Taking log on both sides logK=logKa1+logKa2+logKa3
Phosphoric acid ionizes in three steps with their ionization constant values Ka1, Ka2 and Ka3, respectively, While K is the overall ionization constant. Which of the following statements are true? A. logK=logKa1+logKa2+logKa3 B. H3PO4 is a stronger acid than H2PO4−and HPO42− C. Ka1>Ka2>Ka3 D. Ka1=2Ka3+Ka2 Choose the correct answer from the options given below:
Held on 30 Apr 2025 · Verified 9 Jul 2026.
A and B only
A and C only
B,C and D only
A, B and C only
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For the reaction 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), ΔH = -198 kJ. Which condition favours forward reaction?
The unit of rate constant for a first-order reaction is:
For the reaction $\mathrm{A}(\mathrm{g}) \rightleftharpoons 2 \mathrm{~B}(\mathrm{~g})$, the backward reaction rate constant is higher than the forward reaction rate constant by a factor of 2500 , at 1000 K . [Given : $\mathrm{R}=0.0831 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ] $\mathrm{K}_{\mathrm{p}}$ for the reaction at 1000 K is
$\mathrm{C}(\mathrm{~s})+2 \mathrm{H}_2(\mathrm{~g}) \rightarrow \mathrm{CH}_4(\mathrm{~g}) ; \Delta \mathrm{H}=-74.8 \mathrm{~kJ} \mathrm{~mol}^{-1}$ Which of the following diagrams gives an accurate representation of the above reaction? $[\mathrm{R} \rightarrow$ reactants; $\mathrm{P} \rightarrow$ products $]$
$\begin{aligned} &\text { Consider the following compounds: }\\ &\mathrm{\underline{K}O}_2, \mathrm{H}_2 \mathrm{\underline{O}}_2 \text { and } \mathrm{H}_2 \mathrm{\underline{S}O}_4 \text {. } \end{aligned}$ The oxidation states of the underlined elements in them are, respectively,
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