2I−⟶I2+2e−(Oxidation half-reaction) Eoxi. ∘=−0.536 V. Fe3++e−⟶Fe2+ (Reduction half-reaction) 
E∘=Eoxi ∘+Ered ∘=+ve So, reaction will take place.
A solution contains Fe2+,Fe3+ and I−ions. This solution was treated with iodine at 35∘C. E∘ for Fe3+/Fe2+ is +0.77 V and E∘ for I2/2I−=0.536 V. The favourable redox reaction is
Held on 30 Apr 2011 · Verified 9 Jul 2026.
I2 will be reduced to I−
There will be no redox reaction
I−will be oxidised to I2
Fe2+ will be oxidised to Fe3+
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