Key Idea : The Arrhenius equation is represented as k=Ae−Ea/RT In the given equations, first take log and then compare them. k1=1016e−2000/Tk2=1015e−1000/T On taking log, we get logk1=log1016−2.303T2000logk2=log1015−2.303T1000∵k1=k2 Hence, from Eqs (i) and (ii) T=2.3031000 K