2AB2⇌2AB+B21001−xxx/2 Total mole at equi. =1+2x ∴KP=(1+x/21−x×P)2(1+x/2x×P)2(1+x/2x/2×P) (Here x is degree of dissociation) or KP=2x3P or x3=P2KP or x=(P2KP)1/3
The dissociation equilibrium of a gas AB2 can be represented as, 2AB2( g)⇌2AB(g)+B2( g). The degree of dissociation is ' x ' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant KP and total pressure P is
Held on 30 Apr 2008 · Verified 9 Jul 2026.
(PKp)
(P2KP)
(P2KP)1/3
(P2KP)1/2
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