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The dissociation equilibrium of a gas AB_2 can be represented as, 2 AB_2( ~g) ⇌ 2 AB( g)+ B_2( ~g). The degree of dissociation is ' x ' and is small…

NEET UG 2008 — Chemistry Physical Chemistry

2008mcqhard

The dissociation equilibrium of a gas AB2\mathrm{AB}_2AB2​ can be represented as, 2AB2( g)⇌2AB(g)+B2( g)2 \mathrm{AB}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{g})+\mathrm{B}_2(\mathrm{~g})2AB2​( g)⇌2AB(g)+B2​( g). The degree of dissociation is ' x\mathrm{x}x ' and is small compared to 1. The expression relating the degree of dissociation (x)(\mathrm{x})(x) with equilibrium constant KPK_PKP​ and total pressure P\mathrm{P}P is

Official previous-year question

Held on 30 Apr 2008 · Verified 9 Jul 2026.

Options

  1. A

    (KpP)\left(\frac{K_p}{P}\right)(PKp​​)

  2. B

    (2KPP)\left(\frac{2 K_P}{P}\right)(P2KP​​)

  3. C

    (2KPP)1/3\left(\frac{2 K_P}{P}\right)^{1 / 3}(P2KP​​)1/3

  4. D

    (2KPP)1/2\left(\frac{2 K_P}{P}\right)^{1 / 2}(P2KP​​)1/2

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