I and IV can be used due to presence of anhydrous ZnCl2
(III) which gives alkyl halide due to formation of more stable carbocation.
Which of the following reaction(s) can be used for the preparation of alkyl halides?
I. CH3CH2OH+HCl→Anhyd.ZnCl2
II. CH3CH2OH+HCl⟶
III. (CH3)3COH+HCl⟶
IV. (CH3)2CHOH+HCl→Anhyd.ZnCl2
Held on 30 Apr 2015 · Verified 9 Jul 2026.
I III and IV only
I and II only
IV only
III and IV only
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
Which of the following is a reducing sugar?
Markovnikov's rule is applicable to:
Predict the major product ' P ' in the following sequence of reactions- 
The IUPAC name of CH₃-CO-CH₂-CHO is:
Name the class of enzyme that usually catalyze the following reaction : $\mathrm{S}-\mathrm{G}+\mathrm{S}^{\#} \rightarrow \mathrm{~S}+\mathrm{S}^{\#}-\mathrm{G}$ Where, $G \rightarrow$ a group other than hydrogen $S \rightarrow$ a substrate $\mathrm{S}^{\#} \rightarrow$ another substrate
Work through every NEET UG Organic Chemistry PYQ, year by year.