I and IV can be used due to presence of anhydrous ZnCl2
(III) which gives alkyl halide due to formation of more stable carbocation.
NEET UG 2015 — Chemistry Organic Chemistry
Which of the following reaction(s) can be used for the preparation of alkyl halides?
I. CH3CH2OH+HCl→Anhyd.ZnCl2
II. CH3CH2OH+HCl⟶
III. (CH3)3COH+HCl⟶
IV. (CH3)2CHOH+HCl→Anhyd.ZnCl2
Held on 30 Apr 2015 · Verified 9 Jul 2026.
I III and IV only
I and II only
IV only
III and IV only
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