nN2=RTPV=760×0.082×300(725−25)40×10−3nN2=760×24.628wN2=760×24.628×28 g of N2Weight of N2=760×24.628×28gm%N2=660×24.6128×28×0.251×100=16.77%
In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure.…
NEET UG 2015 — Chemistry Organic Chemistry
2015mcqhard
In Duma's method for estimation of nitrogen, 0.25 g of an organic compound gave 40 mL of nitrogen collected at 300 K temperature and 725 mm pressure. If the aqueous tension at 300 K is 25 mm, the percentage of nitrogen in the compound is:
Official previous-year question
Held on 30 Apr 2015 · Verified 9 Jul 2026.
Options
- A
17.36
- B
18.20
- C
16.76
- D
15.76
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