C2H5OH being a weaker nucleophile, when used as a solvent in case of hindered 1∘ halide, favours SN1 mechanism while C2H5O−being a strong nucleophile in this reaction favours SN2 mechanism.
Consider the reactions (i) ( CH_3 )_2 CH- CH_2 Br stackrel C_2 H_5 OH longrightarrow ( CH_3 )_2 CH - CH_2 OC_2 H_5+ HBr (ii) ( CH_3 )_2 CH- CH_2 Br…
NEET UG 2011 — Chemistry Organic Chemistry
2011mcqhard
Consider the reactions (i) (CH3)2CH−CH2Br⟶C2H5OH(CH3)2CH−CH2OC2H5+HBr (ii) (CH3)2CH−CH2Br⟶C2H5O−(CH3)2CH−CH2OC2H5+Br− The mechanisms of reactions (i) and (ii) are respectively
Official previous-year question
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Options
- A
SN1 and SN2
- B
SN1 and SN1
- C
SN2 and SN2
- D
SN2 and SN1
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