Key Idea:- Molecules having the same number of hybrid orbitals, have same hybridisation and number of hybrid orbitals, H=21[ V+X−C+A] where, V= no. of valence electrons of central atom X= no. of monovalent atoms C= charge on cation A= Charge on anion. (a) In SF4 H=21[6+4−0+0)=5 (b) In I3− H=21[7+2+1]=5 (c) In SbCl52−, H=21[5+5+2)=6 (d) In PCl5, H=21[5+5+0−0]=5 Since, only SbCl52− has different number of hybrid orbitals (ie, 6) from the other given species, its hybridisation is different from the others, ie, sp3d2. (The hybridisation of other species is sp3 d).
In which one of the following species the central atom has the type of hybridisation which is not the same as that present in the other three?
NEET UG 2010 — Chemistry Inorganic Chemistry
2010mcqeasy
In which one of the following species the central atom has the type of hybridisation which is not the same as that present in the other three?
Official previous-year question
Held on 30 Apr 2010 · Verified 9 Jul 2026.
Options
- A
SF4
- B
I3−
- C
SbCl52−
- D
PCl5
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