Chemistry Inorganic Chemistry questions from NEET UG 2022.
Match List-I with List-II : $\begin{array}{|l|l|} \hline \begin{array}{c} \text{List-I} \\ \text{(Complexes)} \end{array} & \begin{array}{c} \text{List-II} \\ \text{(Types)} \end{array} \\ \hline (a) \left[\mathrm{CO}\left(\mathrm{NH}_3\right)_5 \mathrm{NO}_2\right] \mathrm{Cl}_2 & \text{(i) } \text{ionisation} \\ \text{and} \left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{ONO}\right] & \text{isomerism} \\ \mathrm{Cl}_2 & \\ \hline (b) \left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{CO}(\mathrm{CN})_6\right] & \text{(ii) } \text{coordination} \\ \text{and } \left[\mathrm{Cr}(\mathrm{CN})_6\right] & \text{isomerism} \\ {\left[\mathrm{CO}\left(\mathrm{NH}_3\right)_6\right]} & \\ \hline (c) \left[\mathrm{CO}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br} \text{ and} & \text{(iii) } \text{linkage} \\ {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Br}^2\right] \mathrm{SO}_4} & \text{isomerism} \\ \hline (d) \left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3 \text{ and} & \text{(iv) } \text{solvate} \\ {\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}\right] \mathrm{Cl}_2 \cdot \mathrm{H}_2 \mathrm{O}} & \text{isomerism} \\ \hline \end{array}$ Choose the correct answer from the options given below :
Match List-I with List-II : \(\begin{array}{l|l} \text{List-I} & \text{List-II} \\ \text{(Compounds)} & \text{(Molecular formula)} \\ \hline \text { (a) Borax } & \text { (i) } \mathrm{NaBO}_2 \\ \text { (b) Kernite } & \text { (ii) } \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 4 \mathrm{H}_2 \mathrm{O} \\ \text { (c) Orthoboric acid } & \text { (iii) } \mathrm{H}_3 \mathrm{BO}_3 \\ \text { (d) Borax bead } & \text { (iv) } \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O} \end{array}\) Choose the correct answer from the options given below :