Data ⇒n,k,t1+n2kT2+n3kT3=(n1+n2+n3)kT ∴T=n1+n2+n3n1T1+n2T2+n3T3
JEE Main 2011 — Physics Thermodynamics
Three perfect gases at absolute temperatures T1,T2 and T3 are mixed. The masses of molecules are m1, m2 and m3 and the number of molecules are n1,n2 and n3 respectively. Assuming no loss of energy, the final temperature of the mixture is :
Held on 30 Apr 2011 · Verified 6 Jul 2026.
n1+n2+n3n1T1+n2T2+n3T3
n1T1+n2T2+n3T3n1T1+n2T22+n3T32
n1T1+n2T2+n3T3n12T12+n22T22+n32T32
3(T1+T2+T3)
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