Data ⇒n,k,t1+n2kT2+n3kT3=(n1+n2+n3)kT ∴T=n1+n2+n3n1T1+n2T2+n3T3
Three perfect gases at absolute temperatures T_1, T_2 and T_3 are mixed. The masses of molecules are m_1, m_2 and m_3 and the number of molecules are…
JEE Main 2011 — Physics Thermodynamics
Three perfect gases at absolute temperatures T1,T2 and T3 are mixed. The masses of molecules are m1, m2 and m3 and the number of molecules are n1,n2 and n3 respectively. Assuming no loss of energy, the final temperature of the mixture is :
Held on 30 Apr 2011 · Verified 6 Jul 2026.
Options
- A
n1+n2+n3n1T1+n2T2+n3T3
- B
n1T1+n2T2+n3T3n1T1+n2T22+n3T32
- C
n1T1+n2T2+n3T3n12T12+n22T22+n32T32
- D
3(T1+T2+T3)
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